1. |ψ⟩ = α|0⟩+β|1⟩;|α|²+|β|² = 1;概率 = 幅的模方
2. |ψ⟩ = cos(θ/2)|0⟩+e^{iφ}sin(θ/2)|1⟩;P(0) = cos²(θ/2)、P(1) = sin²(θ/2)
3. |0⟩⊗|1⟩ = (0,1,0,0)ᵀ;n 比特 → 2ⁿ 维(300 比特 ≈ 10^90)
4. |Φ⁺⟩ = (|00⟩+|11⟩)/√2;P(00,01,10,11) = (1/2, 0, 0, 1/2)
5. 不可分解判据:ac = 1/√2、ad = 0、bc = 0、bd = 1/√2 无解(反证法四步)
6. U†U = UU† = I ⇒ ⟨ψ′|ψ′⟩ = ⟨ψ|ψ⟩(可逆 + 概率守恒)
7. X|0⟩ = |1⟩;Z|1⟩ = −|1⟩;H|0⟩ = |+⟩、H|1⟩ = |−⟩;H² = I
8. (U₁⊗U₂)(|a⟩⊗|b⟩) = (U₁|a⟩)⊗(U₂|b⟩)(单比特门不产生纠缠)
9. CNOT:|10⟩→|11⟩、|11⟩→|10⟩(其余基态不变);|00⟩ —H⊗I→ —CNOT→ |Φ⁺⟩
10. U = e^{iα}R_z(β)R_y(γ)R_z(δ);两级酉矩阵数 ≤ N(N−1)/2;{H, T, CNOT} 稠密通用