- 题面:$|\psi\rangle = (1/\sqrt{2})|0\rangle + (i/\sqrt{2})|1\rangle$,用朴素点积(分量自己乘自己,不取共轭)计算"长度平方"
- 演算(逐行):
- 分量自乘:$(1/\sqrt{2})^2 = 1/2$;$(i/\sqrt{2})^2 = i^2/2 = -1/2$
- 求和:$1/2 + (-1/2)$ = 0——非零矢量长度为零(AMBER 大字警示)
- 病根:系数是复数,自己乘自己之前必须先取共轭;本课第 7 页将算出正确答案 $1$ ✓
- 本课路线一行:记号(右矢/左矢)→ 运算(内积/范数)→ 演化(幺正)→ 几何(布洛赫球)
类型worked-example(开场钩子,反例演算)