- 命题框:分解 $A = H_R + i\cdot H_I$,$H_R = (A+A^\dagger)/2$、$H_I = (A-A^\dagger)/(2i)$ 均 Hermitian;增广哈密顿量 $\mathcal{K} = H_R\otimes P - H_I\otimes I$($P = -i\partial_\eta$ 自伴)→ $\mathcal{K} = \mathcal{K}^\dagger$ → $e^{-i\mathcal{K}t}$ 酉
- 推导步骤(逐行):
- $\eta$ 表示展开 $P$:$i\partial_t\Phi = \mathcal{K}\Phi$ 化为输运方程 $\partial_t\Phi = -H_R\cdot\partial_\eta\Phi + i H_I\cdot\Phi$(速度 $-H_R$ 的输运 + 相位旋转)
- 交换情形沿特征线积分:$\Phi(t,\eta) = e^{i H_I t}\cdot\Phi_0(\eta - H_R t)$
- 代入初值 $\Phi_0(\eta) = u_0\cdot e^{-\eta}\cdot\Theta(\eta)$:$e^\eta\cdot\Phi(t,\eta) = e^{i H_I t}\cdot e^{H_R t}\cdot u_0 = e^{At}\cdot u_0$——恢复公式
- 演算核对 a(纯相位):$A = i\omega$ → $H_R = 0$、$\mathcal{K} = -\omega I$ → $\Phi = e^{i\omega t}\cdot u_0 e^{-\eta}\Theta$,恢复 $e^\eta\Phi = e^{i\omega t}\cdot u_0$(正是酉演化 ✓)
- 演算核对 b(耗散):$A = -\gamma$ → $\Phi(t,\eta) = u_0\cdot e^{-(\eta+\gamma t)}\cdot\Theta(\eta+\gamma t)$,恢复 $e^\eta\Phi = e^{-\gamma t}\cdot u_0$;范数核对 $\lVert\Phi(t)\rVert^2 = \lVert u_0\rVert^2\cdot\int_0^\infty e^{-2u}\, du = (1/2)\lVert u_0\rVert^2$(与酉性一致 ✓)
- 结果框:任意线性演化(含收缩)被嵌入增广空间的酉动力学;复杂度 $O(\lVert A\rVert_{\max}\cdot t\cdot\mathrm{polylog}(1/\varepsilon)\cdot C_U)$;后选择概率 $\propto \lVert u(t)\rVert^2/\lVert u_0\rVert^2$(解衰减时需振幅放大)
类型definition-derivation(重点页,占满)