1. e^{−βx} 是整函数 → 可取固定大小椭圆;椭圆上 max Re z = (ρ + ρ⁻¹)/2 = (e + 1/e)/2 ≈ 1.543
2. M = max_{E_ρ}|f| ≤ e^{1.543·β‖H‖}
3. 演算:β‖H‖ = 10 → M ≤ e^{15.4} ≈ 5×10⁶
4. 令 2M·ρ^{−d} ≤ ε:d ≥ ln(2M/ε)/ln ρ = ln 2 + 1.543·β‖H‖ + ln(1/ε)
5. 演算:ε = 0.01 → d ≥ 0.69 + 15.4 + 4.6 ≈ 20.7 → d ≈ 21
6. 一般式:d = O(β‖H‖ + log(1/ε))